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Автор felixu95 (15 дней)
This is actually the H2O2 being decomposed into steam and oxygen; the
potassium permanganate is not oxidizing it. H2O2 is a stronger oxidizing
agent than the Potassium permanganate is.

Автор Natasha Oberoi (1 год)
we r given aquous solution od kmno4,otherwise we could have the fun too
!!!!

Автор lambogeek (5 лет)
we used mnO2 in school for catalyst

Автор bla287 (5 лет)
Aahh, the first time I see a video of that reaction where the uploader
actually realizes that H2O2 works as a reducing agent in that case ;)

Автор C For Chemistry (5 лет)
H2O2 is actually dispoprtioned to H2O and O2 is this case, proved that
KMnO4 are really strong!

Автор TheAmmoniacal (2 года)
Just want to file a small complaint, whenever people want to call
themselves educators I get very picky with the facts. In your reaction you
have K2O2 written, this compound do not exist in solution, and is most
likely not formed at all in the reaction. A more accurate one would be:
2MnO4–(aq) + 3H2O2(aq) → 2MnO2(s) + 2H2O(l) + 3O2(g) + 2OH–(aq) ... Where
the K+ is just a spectator ion is canceled from the net ionic reaction.

Автор Smitty Werbenjagermanjensen (5 лет)
Can I dispose of the manganese IV by adding water to make a solution,
adding sodium carbonate, and filtering it off and throwing it out.

Автор Kripo21 (5 лет)
What a mess. :D

Автор C For Chemistry (5 лет)
you can dispose by adding acid, makeing Mn2+ solution.

Автор Alex Woods (2 года)
does any one know were you can buy small amounts of 50 percent hydrogen
peroxide

Автор bla287 (5 лет)
Well, isn't the disproportionation first happening then when there's MnO2?
Because the KMnO4 somehow has to go down from +7 to +4, and thus needing a
reducing agent?

Автор C For Chemistry (5 лет)
Thanks

Автор alinan90 (4 года)
We used Potassium Iodine (KI) and placed it in a closed beaker. The stopper
had pressure sensor attached and that way you can measure how much O2 was
released.

Автор C For Chemistry (5 лет)
85% Hydrogen peroxide reacts in a much more vigorous manner, but I dare not
to try it.

Автор C For Chemistry (5 лет)
I do real science, so I should deliver correct information to all curious
in it.Thanks for your comments and if you see anything wrong from my video,
please let me know.

Автор Hydroxybenzeen (5 лет)
Thanks I did not know that, I tried the experiment myself using 8%
solution. Afther the reaction the remaining liquid had a brownisch collor,
indicating MnO2 had formed.

Автор C For Chemistry (5 лет)
i would say yes vinegar will do

Автор EmeraldxFairy (5 лет)
Great vid! 5*

Автор Hydroxybenzeen (5 лет)
The H2O2 is not oxidised by the potassium permanganate, the KMnO4 only acts
as a cathalyst.

Автор bla287 (5 лет)
What I meant to say first is that I read lots of comments on other vids
where people clkaim that the H2O2 "oxidizes" the KMnO4 which is impossible

Автор C For Chemistry (5 лет)
Nice to meet such an enthusiastic chemist like you, I hope we can still
have such constructive discussion in the future!

Автор solojam (5 лет)
it sounded like the pop happend before they came in contact!

Автор bla287 (5 лет)
No, there's nothing wrong with your vid ;) I just thought the initial
reaction (when there's no MnO2 yet) would be something like this:
Reduction: MnO4(-) + 2 H2O + 3 e(-) → MnO2 + 4 OH(-); E° = +1.7V Oxidation:
H2O2 → O2 + 2 H(+) + 2 e(-) E° = +0.7V So from the potentials, this should
be possible. Of course, later on as there is more MnO2 present, another
more complicated reaction occurs where the MnO2 just catalyzes the
dismutation of H2O2 to H2O and O2, correct me if I'm wrong.

Автор Smitty Werbenjagermanjensen (5 лет)
@Cforchemistry will any acid do?

Автор Aaron Varghese (4 года)
Ok now I know I might be asking a stupid question but, when will we use
this information in our lives?

Автор C For Chemistry (5 лет)
The equation is not balanced.

Автор 4lifebloods (2 года)
Cannabis smoke:)

Автор arnrgrerlrors (5 лет)
you did a mistake...the number of the oxygens is not right....test it
again....:)

Автор C For Chemistry (5 лет)
Actually starts when in contact with KMnO4, but reaction with KMnO4 is
complex, so hard to investigate...

Автор LargeVirus (2 года)
you can do this at home, I do this all the time with different amounts to
produce different effects, like a mercury-like liquid. This can also be
done with 3% peroxide.

Автор C For Chemistry (5 лет)
KMnO4 did react to form MnO2, and MnO2 is the catalyst.

Автор DF110018 (5 лет)
Nice video! Nice chemistry experiment!

Автор elating96 Teracerus (2 года)
CforChemistry, may I ask can I get the pure MnO2 product from the
reaction??? (For example by the filtration) Thank you very much :D :)

Автор Dearnna Clinkscales (4 года)
is there a way of measuring the amount of gas given off? if so how and is
it safe for a classroom experment?

Автор bla287 (5 лет)
Thanks ;)

Автор Leighton Scheer (3 года)
what about 3% H2O2

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